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9x^2-24x-105=0
a = 9; b = -24; c = -105;
Δ = b2-4ac
Δ = -242-4·9·(-105)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-66}{2*9}=\frac{-42}{18} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+66}{2*9}=\frac{90}{18} =5 $
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